2/3(d+12)=1/2(2d-6)

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Solution for 2/3(d+12)=1/2(2d-6) equation: 



2/3(d+12)=1/2(2d-6)

We move all terms to the left:

2/3(d+12)-(1/2(2d-6))=0



Domain of the equation: 3(d+12)!=0

d∈R





Domain of the equation: 2(2d-6))!=0

d∈R



We calculate fractions


(4d2/(3(d+12)*2(2d-6)))+(-3dd/(3(d+12)*2(2d-6)))=0



We calculate terms in parentheses: +(4d2/(3(d+12)*2(2d-6))), so:

4d2/(3(d+12)*2(2d-6))

We multiply all the terms by the denominator


4d2

We add all the numbers together, and all the variables

4d^2

Back to the equation:

+(4d^2)





We calculate terms in parentheses: +(-3dd/(3(d+12)*2(2d-6))), so:

-3dd/(3(d+12)*2(2d-6))

We multiply all the terms by the denominator


-3dd

Back to the equation:

+(-3dd)



We get rid of parentheses

4d^2-3dd=0

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