2/3(j+19)=4

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Solution for 2/3(j+19)=4 equation:



2/3(j+19)=4
We move all terms to the left:
2/3(j+19)-(4)=0
Domain of the equation: 3(j+19)!=0
j∈R
We multiply all the terms by the denominator
-4*3(j+19)+2=0
Wy multiply elements
-12j(j+2=0

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