2/3(k+10)=2/3k

Solution for 2/3(k+10)=2/3k equation:

2/3(k+10)=2/3k

We move all terms to the left:

2/3(k+10)-(2/3k)=0


Domain of the equation: 3(k+10)!=0

k∈R



Domain of the equation: 3k)!=0

k!=0/1

k!=0

k∈R


We add all the numbers together, and all the variables

2/3(k+10)-(+2/3k)=0

We get rid of parentheses

2/3(k+10)-2/3k=0

We calculate fractions


6k/(9k^2+90k)+(-6kk/(9k^2+90k)=0


We calculate terms in parentheses: +(-6kk/(9k^2+90k), so:

-6kk/(9k^2+90k

We multiply all the terms by the denominator


-6kk

Back to the equation:

+(-6kk)


We get rid of parentheses

6k/(9k^2+90k)-6kk=0

We multiply all the terms by the denominator


6k-6kk*(9k^2+90k)=0

We multiply parentheses

-54k^3-540k^2+6k=0

We do not support ekpression: k^3