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2/3(m+3)-4/15(3m+7)=4/5
We move all terms to the left:
2/3(m+3)-4/15(3m+7)-(4/5)=0
Domain of the equation: 3(m+3)!=0
m∈R
Domain of the equation: 15(3m+7)!=0We add all the numbers together, and all the variables
m∈R
2/3(m+3)-4/15(3m+7)-(+4/5)=0
We get rid of parentheses
2/3(m+3)-4/15(3m+7)-4/5=0
We calculate fractions
(150m3/(3(m+3)*15(3m+7)*5)+(-60mm/(3(m+3)*15(3m+7)*5)+(-180m^2m/(3(m+3)*15(3m+7)*5)=0
We calculate terms in parentheses: +(150m3/(3(m+3)*15(3m+7)*5)+(-60mm/(3(m+3)*15(3m+7)*5)+(-180m^2m/(3(m+3)*15(3m+7)*5), so:
150m3/(3(m+3)*15(3m+7)*5)+(-60mm/(3(m+3)*15(3m+7)*5)+(-180m^2m/(3(m+3)*15(3m+7)*5
We can not solve this equation
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