2/3(m+4)=1/3(4m+12)

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Solution for 2/3(m+4)=1/3(4m+12) equation: 



2/3(m+4)=1/3(4m+12)

We move all terms to the left:

2/3(m+4)-(1/3(4m+12))=0



Domain of the equation: 3(m+4)!=0

m∈R





Domain of the equation: 3(4m+12))!=0

m∈R



We calculate fractions


(6m4/(3(m+4)*3(4m+12)))+(-3mm/(3(m+4)*3(4m+12)))=0



We calculate terms in parentheses: +(6m4/(3(m+4)*3(4m+12))), so:

6m4/(3(m+4)*3(4m+12))

We multiply all the terms by the denominator


6m4

We add all the numbers together, and all the variables

6m^4

We do not support empression: m^4

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