2/3(m-9)=1/3(m-27)

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Solution for 2/3(m-9)=1/3(m-27) equation: 



2/3(m-9)=1/3(m-27)

We move all terms to the left:

2/3(m-9)-(1/3(m-27))=0



Domain of the equation: 3(m-9)!=0

m∈R





Domain of the equation: 3(m-27))!=0

m∈R



We calculate fractions


(6mm/(3(m-9)*3(m-27)))+(-3mm/(3(m-9)*3(m-27)))=0



We calculate terms in parentheses: +(6mm/(3(m-9)*3(m-27))), so:

6mm/(3(m-9)*3(m-27))

We multiply all the terms by the denominator


6mm

Back to the equation:

+(6mm)





We calculate terms in parentheses: +(-3mm/(3(m-9)*3(m-27))), so:

-3mm/(3(m-9)*3(m-27))

We multiply all the terms by the denominator


-3mm

Back to the equation:

+(-3mm)



We get rid of parentheses

6mm-3mm=0

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