2/3(n+2)+2=1/9(2n-6)

Solution for 2/3(n+2)+2=1/9(2n-6) equation:

2/3(n+2)+2=1/9(2n-6)

We move all terms to the left:

2/3(n+2)+2-(1/9(2n-6))=0


Domain of the equation: 3(n+2)!=0

n∈R



Domain of the equation: 9(2n-6))!=0

n∈R


We calculate fractions


(18n2/(3(n+2)*9(2n-6)))+(-3nn/(3(n+2)*9(2n-6)))+2=0


We calculate terms in parentheses: +(18n2/(3(n+2)*9(2n-6))), so:

18n2/(3(n+2)*9(2n-6))

We multiply all the terms by the denominator


18n2

We add all the numbers together, and all the variables

18n^2

Back to the equation:

+(18n^2)



We calculate terms in parentheses: +(-3nn/(3(n+2)*9(2n-6))), so:

-3nn/(3(n+2)*9(2n-6))

We multiply all the terms by the denominator


-3nn

Back to the equation:

+(-3nn)


We get rid of parentheses

18n^2-3nn+2=0

We move all terms containing n to the left, all other terms to the right

18n^2-3nn=-2