2/3(p+3)=5/6(p-4)

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Solution for 2/3(p+3)=5/6(p-4) equation: 



2/3(p+3)=5/6(p-4)

We move all terms to the left:

2/3(p+3)-(5/6(p-4))=0



Domain of the equation: 3(p+3)!=0

p∈R





Domain of the equation: 6(p-4))!=0

p∈R



We calculate fractions


(12pp/(3(p+3)*6(p-4)))+(-15pp/(3(p+3)*6(p-4)))=0



We calculate terms in parentheses: +(12pp/(3(p+3)*6(p-4))), so:

12pp/(3(p+3)*6(p-4))

We multiply all the terms by the denominator


12pp

Back to the equation:

+(12pp)





We calculate terms in parentheses: +(-15pp/(3(p+3)*6(p-4))), so:

-15pp/(3(p+3)*6(p-4))

We multiply all the terms by the denominator


-15pp

Back to the equation:

+(-15pp)



We get rid of parentheses

12pp-15pp=0

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