2/3(q-3)=1/4(q+7)

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Solution for 2/3(q-3)=1/4(q+7) equation: 



2/3(q-3)=1/4(q+7)

We move all terms to the left:

2/3(q-3)-(1/4(q+7))=0



Domain of the equation: 3(q-3)!=0

q∈R





Domain of the equation: 4(q+7))!=0

q∈R



We calculate fractions


(8qq/(3(q-3)*4(q+7)))+(-3qq/(3(q-3)*4(q+7)))=0



We calculate terms in parentheses: +(8qq/(3(q-3)*4(q+7))), so:

8qq/(3(q-3)*4(q+7))

We multiply all the terms by the denominator


8qq

Back to the equation:

+(8qq)





We calculate terms in parentheses: +(-3qq/(3(q-3)*4(q+7))), so:

-3qq/(3(q-3)*4(q+7))

We multiply all the terms by the denominator


-3qq

Back to the equation:

+(-3qq)



We get rid of parentheses

8qq-3qq=0

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