2/3(r-1)-1/2(5r-2)=100/3

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Solution for 2/3(r-1)-1/2(5r-2)=100/3 equation: 



2/3(r-1)-1/2(5r-2)=100/3

We move all terms to the left:

2/3(r-1)-1/2(5r-2)-(100/3)=0



Domain of the equation: 3(r-1)!=0

r∈R





Domain of the equation: 2(5r-2)!=0

r∈R



We add all the numbers together, and all the variables

2/3(r-1)-1/2(5r-2)-(+100/3)=0

We get rid of parentheses

2/3(r-1)-1/2(5r-2)-100/3=0

We calculate fractions


(4r5/(3(r-1)*2(5r-2)*3)+(-9rr/(3(r-1)*2(5r-2)*3)+(-200r5/(3(r-1)*2(5r-2)*3)=0



We calculate terms in parentheses: +(4r5/(3(r-1)*2(5r-2)*3)+(-9rr/(3(r-1)*2(5r-2)*3)+(-200r5/(3(r-1)*2(5r-2)*3), so:

4r5/(3(r-1)*2(5r-2)*3)+(-9rr/(3(r-1)*2(5r-2)*3)+(-200r5/(3(r-1)*2(5r-2)*3

We can not solve this equation

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