2/3(t+6)=1/3-t

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Solution for 2/3(t+6)=1/3-t equation: 


t in (-oo:+oo)

(2/3)*(t+6) = 1/3-t // - 1/3-t

(2/3)*(t+6)+t-(1/3) = 0

(2/3)*(t+6)+t-1/3 = 0

2/3*(t+6)+t-1/3 = 0

(2/3*3*(t+6))/3+(3*t)/3-1/3 = 0

2/3*3*(t+6)+3*t-1 = 0

5*t-1+12 = 0

5*t+11 = 0

(5*t+11)/3 = 0

(5*t+11)/3 = 0 // * 3

5*t+11 = 0

5*t+11 = 0 // - 11

5*t = -11 // : 5

t = -11/5

t = -11/5

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