2/3(t-6)=3/4(2-3t)

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Solution for 2/3(t-6)=3/4(2-3t) equation: 



2/3(t-6)=3/4(2-3t)

We move all terms to the left:

2/3(t-6)-(3/4(2-3t))=0



Domain of the equation: 3(t-6)!=0

t∈R





Domain of the equation: 4(2-3t))!=0

t∈R



We add all the numbers together, and all the variables

2/3(t-6)-(3/4(-3t+2))=0

We calculate fractions


(8t(-)/(3(t-6)*4(-3t+2)))+(-9tt/(3(t-6)*4(-3t+2)))=0



We calculate terms in parentheses: +(8t(-)/(3(t-6)*4(-3t+2))), so:

8t(-)/(3(t-6)*4(-3t+2))

We add all the numbers together, and all the variables

8t0/(3(t-6)*4(-3t+2))

We multiply all the terms by the denominator


8t0

We add all the numbers together, and all the variables

8t

Back to the equation:

+(8t)





We calculate terms in parentheses: +(-9tt/(3(t-6)*4(-3t+2))), so:

-9tt/(3(t-6)*4(-3t+2))

We multiply all the terms by the denominator


-9tt

Back to the equation:

+(-9tt)



We get rid of parentheses

8t-9tt=0

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