2/3(w+4)-2=5/6(2+w)

Solution for 2/3(w+4)-2=5/6(2+w) equation:

2/3(w+4)-2=5/6(2+w)

We move all terms to the left:

2/3(w+4)-2-(5/6(2+w))=0


Domain of the equation: 3(w+4)!=0

w∈R



Domain of the equation: 6(2+w))!=0

w∈R


We add all the numbers together, and all the variables

2/3(w+4)-(5/6(w+2))-2=0

We calculate fractions


(12ww/(3(w+4)*6(w+2)))+(-15ww/(3(w+4)*6(w+2)))-2=0


We calculate terms in parentheses: +(12ww/(3(w+4)*6(w+2))), so:

12ww/(3(w+4)*6(w+2))

We multiply all the terms by the denominator


12ww

Back to the equation:

+(12ww)



We calculate terms in parentheses: +(-15ww/(3(w+4)*6(w+2))), so:

-15ww/(3(w+4)*6(w+2))

We multiply all the terms by the denominator


-15ww

Back to the equation:

+(-15ww)


We get rid of parentheses

12ww-15ww-2=0

We move all terms containing w to the left, all other terms to the right

12ww-15ww=2