2/3(w-5)=3/4(w+2)

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Solution for 2/3(w-5)=3/4(w+2) equation: 



2/3(w-5)=3/4(w+2)

We move all terms to the left:

2/3(w-5)-(3/4(w+2))=0



Domain of the equation: 3(w-5)!=0

w∈R





Domain of the equation: 4(w+2))!=0

w∈R



We calculate fractions


(8ww/(3(w-5)*4(w+2)))+(-9ww/(3(w-5)*4(w+2)))=0



We calculate terms in parentheses: +(8ww/(3(w-5)*4(w+2))), so:

8ww/(3(w-5)*4(w+2))

We multiply all the terms by the denominator


8ww

Back to the equation:

+(8ww)





We calculate terms in parentheses: +(-9ww/(3(w-5)*4(w+2))), so:

-9ww/(3(w-5)*4(w+2))

We multiply all the terms by the denominator


-9ww

Back to the equation:

+(-9ww)



We get rid of parentheses

8ww-9ww=0

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