2/3(x)+10=16

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Solution for 2/3(x)+10=16 equation: 



2/3(x)+10=16

We move all terms to the left:

2/3(x)+10-(16)=0



Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R



We add all the numbers together, and all the variables

2/3x-6=0

We multiply all the terms by the denominator


-6*3x+2=0

Wy multiply elements

-18x+2=0

We move all terms containing x to the left, all other terms to the right

-18x=-2

x=-2/-18

x=1/9

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