2/3(x)+10=16

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Solution for 2/3(x)+10=16 equation:



2/3(x)+10=16
We move all terms to the left:
2/3(x)+10-(16)=0
Domain of the equation: 3x!=0
x!=0/3
x!=0
x∈R
We add all the numbers together, and all the variables
2/3x-6=0
We multiply all the terms by the denominator
-6*3x+2=0
Wy multiply elements
-18x+2=0
We move all terms containing x to the left, all other terms to the right
-18x=-2
x=-2/-18
x=1/9

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