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2/3(x+1)+3/4(x-1)=4/3
We move all terms to the left:
2/3(x+1)+3/4(x-1)-(4/3)=0
Domain of the equation: 3(x+1)!=0
x∈R
Domain of the equation: 4(x-1)!=0We add all the numbers together, and all the variables
x∈R
2/3(x+1)+3/4(x-1)-(+4/3)=0
We get rid of parentheses
2/3(x+1)+3/4(x-1)-4/3=0
We calculate fractions
(8xx/(3(x+1)*4(x-1)*3)+(27xx/(3(x+1)*4(x-1)*3)+(-16xx/(3(x+1)*4(x-1)*3)=0
We calculate terms in parentheses: +(8xx/(3(x+1)*4(x-1)*3)+(27xx/(3(x+1)*4(x-1)*3)+(-16xx/(3(x+1)*4(x-1)*3), so:
8xx/(3(x+1)*4(x-1)*3)+(27xx/(3(x+1)*4(x-1)*3)+(-16xx/(3(x+1)*4(x-1)*3
We can not solve this equation
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