2/3(x+12)=4/5(x-10)

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Solution for 2/3(x+12)=4/5(x-10) equation: 



2/3(x+12)=4/5(x-10)

We move all terms to the left:

2/3(x+12)-(4/5(x-10))=0



Domain of the equation: 3(x+12)!=0

x∈R





Domain of the equation: 5(x-10))!=0

x∈R



We calculate fractions


(10xx/(3(x+12)*5(x-10)))+(-12xx/(3(x+12)*5(x-10)))=0



We calculate terms in parentheses: +(10xx/(3(x+12)*5(x-10))), so:

10xx/(3(x+12)*5(x-10))

We multiply all the terms by the denominator


10xx

Back to the equation:

+(10xx)





We calculate terms in parentheses: +(-12xx/(3(x+12)*5(x-10))), so:

-12xx/(3(x+12)*5(x-10))

We multiply all the terms by the denominator


-12xx

Back to the equation:

+(-12xx)



We get rid of parentheses

10xx-12xx=0

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