2/3(x+2)-(x+4)=3x+2

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Solution for 2/3(x+2)-(x+4)=3x+2 equation: 



2/3(x+2)-(x+4)=3x+2

We move all terms to the left:

2/3(x+2)-(x+4)-(3x+2)=0



Domain of the equation: 3(x+2)!=0

x∈R



We get rid of parentheses

2/3(x+2)-x-3x-4-2=0

We multiply all the terms by the denominator


-x*3(x+2)-3x*3(x+2)-4*3(x+2)-2*3(x+2)+2=0

Wy multiply elements

-3x^2(x-9x^2(x-12x(x-6x(x+2=0

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