2/3(x+2)-1/2=3/4(x+2)

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Solution for 2/3(x+2)-1/2=3/4(x+2) equation: 



2/3(x+2)-1/2=3/4(x+2)

We move all terms to the left:

2/3(x+2)-1/2-(3/4(x+2))=0



Domain of the equation: 3(x+2)!=0

x∈R





Domain of the equation: 4(x+2))!=0

x∈R



We calculate fractions


(-12x^2x/(3(x+2)*4(x+2))*2)+(16xx/(3(x+2)*4(x+2))*2)+(-(3*3(x+2)*2)/(3(x+2)*4(x+2))*2)=0



We calculate terms in parentheses: +(-12x^2x/(3(x+2)*4(x+2))*2), so:

-12x^2x/(3(x+2)*4(x+2))*2

We multiply all the terms by the denominator


-12x^2x

Back to the equation:

+(-12x^2x)





We calculate terms in parentheses: +(16xx/(3(x+2)*4(x+2))*2), so:

16xx/(3(x+2)*4(x+2))*2

We multiply all the terms by the denominator


16xx

Back to the equation:

+(16xx)





We calculate terms in parentheses: +(-(3*3(x+2)*2)/(3(x+2)*4(x+2))*2), so:

-(3*3(x+2)*2)/(3(x+2)*4(x+2))*2

We multiply all the terms by the denominator


-(3*3(x+2)*2)



We calculate terms in parentheses: -(3*3(x+2)*2), so:

3*3(x+2)*2

Wy multiply elements

18x(x

Back to the equation:

-(18x(x)



Back to the equation:

+(-(18xx)



We get rid of parentheses

-12x^2x+16xx+(-18xx=0

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