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2/3(x+3)-3/5(2x-3)=2
We move all terms to the left:
2/3(x+3)-3/5(2x-3)-(2)=0
Domain of the equation: 3(x+3)!=0
x∈R
Domain of the equation: 5(2x-3)!=0We calculate fractions
x∈R
(10x2/(3(x+3)*5(2x-3))+(-9xx/(3(x+3)*5(2x-3))-2=0
We can not solve this equation
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