2/3(x+3)=3/4(2x-5)

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Solution for 2/3(x+3)=3/4(2x-5) equation: 



2/3(x+3)=3/4(2x-5)

We move all terms to the left:

2/3(x+3)-(3/4(2x-5))=0



Domain of the equation: 3(x+3)!=0

x∈R





Domain of the equation: 4(2x-5))!=0

x∈R



We calculate fractions


(8x2/(3(x+3)*4(2x-5)))+(-9xx/(3(x+3)*4(2x-5)))=0



We calculate terms in parentheses: +(8x2/(3(x+3)*4(2x-5))), so:

8x2/(3(x+3)*4(2x-5))

We multiply all the terms by the denominator


8x2

We add all the numbers together, and all the variables

8x^2

Back to the equation:

+(8x^2)





We calculate terms in parentheses: +(-9xx/(3(x+3)*4(2x-5))), so:

-9xx/(3(x+3)*4(2x-5))

We multiply all the terms by the denominator


-9xx

Back to the equation:

+(-9xx)



We get rid of parentheses

8x^2-9xx=0

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