2/3(x+3)=x+5

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Solution for 2/3(x+3)=x+5 equation: 



2/3(x+3)=x+5

We move all terms to the left:

2/3(x+3)-(x+5)=0



Domain of the equation: 3(x+3)!=0

x∈R



We get rid of parentheses

2/3(x+3)-x-5=0

We multiply all the terms by the denominator


-x*3(x+3)-5*3(x+3)+2=0

Wy multiply elements

-3x^2(x-15x(x+2=0

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