2/3(x+4)+2x-3=10

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Solution for 2/3(x+4)+2x-3=10 equation: 



2/3(x+4)+2x-3=10

We move all terms to the left:

2/3(x+4)+2x-3-(10)=0



Domain of the equation: 3(x+4)!=0

x∈R



We add all the numbers together, and all the variables

2x+2/3(x+4)-13=0

We multiply all the terms by the denominator


2x*3(x+4)-13*3(x+4)+2=0

Wy multiply elements

6x^2(x-39x(x+2=0

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