2/3(x+4)=1/2(2x-7)

Solution for 2/3(x+4)=1/2(2x-7) equation:

2/3(x+4)=1/2(2x-7)

We move all terms to the left:

2/3(x+4)-(1/2(2x-7))=0


Domain of the equation: 3(x+4)!=0

x∈R



Domain of the equation: 2(2x-7))!=0

x∈R


We calculate fractions


(4x2/(3(x+4)*2(2x-7)))+(-3xx/(3(x+4)*2(2x-7)))=0


We calculate terms in parentheses: +(4x2/(3(x+4)*2(2x-7))), so:

4x2/(3(x+4)*2(2x-7))

We multiply all the terms by the denominator


4x2

We add all the numbers together, and all the variables

4x^2

Back to the equation:

+(4x^2)



We calculate terms in parentheses: +(-3xx/(3(x+4)*2(2x-7))), so:

-3xx/(3(x+4)*2(2x-7))

We multiply all the terms by the denominator


-3xx

Back to the equation:

+(-3xx)


We get rid of parentheses

4x^2-3xx=0