2/3(x+4)=1/3(x+12)

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Solution for 2/3(x+4)=1/3(x+12) equation: 



2/3(x+4)=1/3(x+12)

We move all terms to the left:

2/3(x+4)-(1/3(x+12))=0



Domain of the equation: 3(x+4)!=0

x∈R





Domain of the equation: 3(x+12))!=0

x∈R



We calculate fractions


(6xx/(3(x+4)*3(x+12)))+(-3xx/(3(x+4)*3(x+12)))=0



We calculate terms in parentheses: +(6xx/(3(x+4)*3(x+12))), so:

6xx/(3(x+4)*3(x+12))

We multiply all the terms by the denominator


6xx

Back to the equation:

+(6xx)





We calculate terms in parentheses: +(-3xx/(3(x+4)*3(x+12))), so:

-3xx/(3(x+4)*3(x+12))

We multiply all the terms by the denominator


-3xx

Back to the equation:

+(-3xx)



We get rid of parentheses

6xx-3xx=0

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