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2/3(x+4)=3/5(5x-3)
We move all terms to the left:
2/3(x+4)-(3/5(5x-3))=0
Domain of the equation: 3(x+4)!=0
x∈R
Domain of the equation: 5(5x-3))!=0We calculate fractions
x∈R
(10x5/(3(x+4)*5(5x-3)))+(-9xx/(3(x+4)*5(5x-3)))=0
We calculate terms in parentheses: +(10x5/(3(x+4)*5(5x-3))), so:
10x5/(3(x+4)*5(5x-3))
We multiply all the terms by the denominator
10x5
We add all the numbers together, and all the variables
10x^5
We do not support expression: x^5
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