2/3(x+5)+3/4x=5/2x

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Solution for 2/3(x+5)+3/4x=5/2x equation: 



2/3(x+5)+3/4x=5/2x

We move all terms to the left:

2/3(x+5)+3/4x-(5/2x)=0



Domain of the equation: 3(x+5)!=0

x∈R





Domain of the equation: 4x!=0

x!=0/4

x!=0

x∈R





Domain of the equation: 2x)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

2/3(x+5)+3/4x-(+5/2x)=0

We get rid of parentheses

2/3(x+5)+3/4x-5/2x=0

We calculate fractions


(18x^2x/(3(x+5)*4x*2x)+(-60x^2x/(3(x+5)*4x*2x)+32x^2/(3(x+5)*4x*2x)=0



We calculate terms in parentheses: +(18x^2x/(3(x+5)*4x*2x)+(-60x^2x/(3(x+5)*4x*2x)+32x^2/(3(x+5)*4x*2x), so:

18x^2x/(3(x+5)*4x*2x)+(-60x^2x/(3(x+5)*4x*2x)+32x^2/(3(x+5)*4x*2x

We can not solve this equation

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