2/3(x+6)=-2/5(x-9)

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Solution for 2/3(x+6)=-2/5(x-9) equation: 



2/3(x+6)=-2/5(x-9)

We move all terms to the left:

2/3(x+6)-(-2/5(x-9))=0



Domain of the equation: 3(x+6)!=0

x∈R





Domain of the equation: 5(x-9))!=0

x∈R



We calculate fractions


(10xx/(3(x+6)*5(x-9)))+(-(-6xx)/(3(x+6)*5(x-9)))=0



We calculate terms in parentheses: +(10xx/(3(x+6)*5(x-9))), so:

10xx/(3(x+6)*5(x-9))

We multiply all the terms by the denominator


10xx

Back to the equation:

+(10xx)





We calculate terms in parentheses: +(-(-6xx)/(3(x+6)*5(x-9))), so:

-(-6xx)/(3(x+6)*5(x-9))

We multiply all the terms by the denominator


-(-6xx)

We get rid of parentheses

6xx

Back to the equation:

+(6xx)

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