2/3(x-2)+1/2(3-x)=1/3

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Solution for 2/3(x-2)+1/2(3-x)=1/3 equation: 



2/3(x-2)+1/2(3-x)=1/3

We move all terms to the left:

2/3(x-2)+1/2(3-x)-(1/3)=0



Domain of the equation: 3(x-2)!=0

x∈R





Domain of the equation: 2(3-x)!=0

x∈R



We add all the numbers together, and all the variables

2/3(x-2)+1/2(-1x+3)-(+1/3)=0

We get rid of parentheses

2/3(x-2)+1/2(-1x+3)-1/3=0

We calculate fractions


(4x(-)/(3(x-2)*2(-1x+3)*3)+(9xx/(3(x-2)*2(-1x+3)*3)+(-2x(-)/(3(x-2)*2(-1x+3)*3)=0



We calculate terms in parentheses: +(4x(-)/(3(x-2)*2(-1x+3)*3)+(9xx/(3(x-2)*2(-1x+3)*3)+(-2x(-)/(3(x-2)*2(-1x+3)*3), so:

4x(-)/(3(x-2)*2(-1x+3)*3)+(9xx/(3(x-2)*2(-1x+3)*3)+(-2x(-)/(3(x-2)*2(-1x+3)*3

We can not solve this equation

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