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2/3(x-3)+11/2(x+1)=12/3
We move all terms to the left:
2/3(x-3)+11/2(x+1)-(12/3)=0
Domain of the equation: 3(x-3)!=0
x∈R
Domain of the equation: 2(x+1)!=0We add all the numbers together, and all the variables
x∈R
2/3(x-3)+11/2(x+1)-4=0
We calculate fractions
(4xx/(3(x-3)*2(x+1))+(33xx/(3(x-3)*2(x+1))-4=0
We can not solve this equation
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