2/3(x-3)+3/4x=x

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Solution for 2/3(x-3)+3/4x=x equation: 



2/3(x-3)+3/4x=x

We move all terms to the left:

2/3(x-3)+3/4x-(x)=0



Domain of the equation: 3(x-3)!=0

x∈R





Domain of the equation: 4x!=0

x!=0/4

x!=0

x∈R



We add all the numbers together, and all the variables

-1x+2/3(x-3)+3/4x=0

We calculate fractions


-1x+8x/(12x^2-36x)+(9xx/(12x^2-36x)=0



We calculate terms in parentheses: +(9xx/(12x^2-36x), so:

9xx/(12x^2-36x

We multiply all the terms by the denominator


9xx

Back to the equation:

+(9xx)



We multiply all the terms by the denominator


-1x*(12x^2-36x)+8x+9xx*(12x^2-36x)=0

We add all the numbers together, and all the variables

8x-1x*(12x^2-36x)+9xx*(12x^2-36x)=0

We multiply parentheses

-12x^3+36x^2+108x^3-324x^2+8x=0

We do not support expression: x^3

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