2/3(x-3)+6=1/6(4x=24)

Solution for 2/3(x-3)+6=1/6(4x=24) equation:

2/3(x-3)+6=1/6(4x=24)

We move all terms to the left:

2/3(x-3)+6-(1/6(4x)=0


Domain of the equation: 3(x-3)!=0

x∈R



Domain of the equation: 64x+6!=0

We move all terms containing x to the left, all other terms to the right

64x!=-6

x!=-6/64

x!=-3/32

x∈R


We calculate fractions


(128x+6)/(192x^2-576x+6)+(-3xx/(192x^2-576x+6)=0


We calculate terms in parentheses: +(-3xx/(192x^2-576x+6), so:

-3xx/(192x^2-576x+6

We multiply all the terms by the denominator


-3xx

Back to the equation:

+(-3xx)


We get rid of parentheses

(128x+6)/(192x^2-576x+6)-3xx=0

We multiply all the terms by the denominator


(128x+6)-3xx*(192x^2-576x+6)=0

We multiply parentheses

-576x^3+1728x^2+(128x+6)-18x=0

We get rid of parentheses

-576x^3+1728x^2+128x-18x+6=0

We do not support expression: x^3