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2/3(x-4)=-5x+1
We move all terms to the left:
2/3(x-4)-(-5x+1)=0
Domain of the equation: 3(x-4)!=0We get rid of parentheses
x∈R
2/3(x-4)+5x-1=0
We multiply all the terms by the denominator
5x*3(x-4)-1*3(x-4)+2=0
Wy multiply elements
15x^2(x-3x(x+2=0
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