2/3(x-4)=1/2(2x-6)

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Solution for 2/3(x-4)=1/2(2x-6) equation: 



2/3(x-4)=1/2(2x-6)

We move all terms to the left:

2/3(x-4)-(1/2(2x-6))=0



Domain of the equation: 3(x-4)!=0

x∈R





Domain of the equation: 2(2x-6))!=0

x∈R



We calculate fractions


(4x2/(3(x-4)*2(2x-6)))+(-3xx/(3(x-4)*2(2x-6)))=0



We calculate terms in parentheses: +(4x2/(3(x-4)*2(2x-6))), so:

4x2/(3(x-4)*2(2x-6))

We multiply all the terms by the denominator


4x2

We add all the numbers together, and all the variables

4x^2

Back to the equation:

+(4x^2)





We calculate terms in parentheses: +(-3xx/(3(x-4)*2(2x-6))), so:

-3xx/(3(x-4)*2(2x-6))

We multiply all the terms by the denominator


-3xx

Back to the equation:

+(-3xx)



We get rid of parentheses

4x^2-3xx=0

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