2/3(x-7)=-11/2(x+4)

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Solution for 2/3(x-7)=-11/2(x+4) equation: 



2/3(x-7)=-11/2(x+4)

We move all terms to the left:

2/3(x-7)-(-11/2(x+4))=0



Domain of the equation: 3(x-7)!=0

x∈R





Domain of the equation: 2(x+4))!=0

x∈R



We calculate fractions


(4xx/(3(x-7)*2(x+4)))+(-(-33xx)/(3(x-7)*2(x+4)))=0



We calculate terms in parentheses: +(4xx/(3(x-7)*2(x+4))), so:

4xx/(3(x-7)*2(x+4))

We multiply all the terms by the denominator


4xx

Back to the equation:

+(4xx)





We calculate terms in parentheses: +(-(-33xx)/(3(x-7)*2(x+4))), so:

-(-33xx)/(3(x-7)*2(x+4))

We multiply all the terms by the denominator


-(-33xx)

We get rid of parentheses

33xx

Back to the equation:

+(33xx)

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