2/3(x-7)=-11/2(x+4)

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Solution for 2/3(x-7)=-11/2(x+4) equation:



2/3(x-7)=-11/2(x+4)
We move all terms to the left:
2/3(x-7)-(-11/2(x+4))=0
Domain of the equation: 3(x-7)!=0
x∈R
Domain of the equation: 2(x+4))!=0
x∈R
We calculate fractions
(4xx/(3(x-7)*2(x+4)))+(-(-33xx)/(3(x-7)*2(x+4)))=0
We calculate terms in parentheses: +(4xx/(3(x-7)*2(x+4))), so:
4xx/(3(x-7)*2(x+4))
We multiply all the terms by the denominator
4xx
Back to the equation:
+(4xx)
We calculate terms in parentheses: +(-(-33xx)/(3(x-7)*2(x+4))), so:
-(-33xx)/(3(x-7)*2(x+4))
We multiply all the terms by the denominator
-(-33xx)
We get rid of parentheses
33xx
Back to the equation:
+(33xx)

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