2/3(x-7)=-2/3(x+4)

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Solution for 2/3(x-7)=-2/3(x+4) equation: 



2/3(x-7)=-2/3(x+4)

We move all terms to the left:

2/3(x-7)-(-2/3(x+4))=0



Domain of the equation: 3(x-7)!=0

x∈R





Domain of the equation: 3(x+4))!=0

x∈R



We calculate fractions


(6xx/(3(x-7)*3(x+4)))+(-(-6xx)/(3(x-7)*3(x+4)))=0



We calculate terms in parentheses: +(6xx/(3(x-7)*3(x+4))), so:

6xx/(3(x-7)*3(x+4))

We multiply all the terms by the denominator


6xx

Back to the equation:

+(6xx)





We calculate terms in parentheses: +(-(-6xx)/(3(x-7)*3(x+4))), so:

-(-6xx)/(3(x-7)*3(x+4))

We multiply all the terms by the denominator


-(-6xx)

We get rid of parentheses

6xx

Back to the equation:

+(6xx)

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