2/3(x-7)=3/4(x+5)

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Solution for 2/3(x-7)=3/4(x+5) equation: 



2/3(x-7)=3/4(x+5)

We move all terms to the left:

2/3(x-7)-(3/4(x+5))=0



Domain of the equation: 3(x-7)!=0

x∈R





Domain of the equation: 4(x+5))!=0

x∈R



We calculate fractions


(8xx/(3(x-7)*4(x+5)))+(-9xx/(3(x-7)*4(x+5)))=0



We calculate terms in parentheses: +(8xx/(3(x-7)*4(x+5))), so:

8xx/(3(x-7)*4(x+5))

We multiply all the terms by the denominator


8xx

Back to the equation:

+(8xx)





We calculate terms in parentheses: +(-9xx/(3(x-7)*4(x+5))), so:

-9xx/(3(x-7)*4(x+5))

We multiply all the terms by the denominator


-9xx

Back to the equation:

+(-9xx)



We get rid of parentheses

8xx-9xx=0

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