2/3(x-9)=1/3(2x-6)

Solution for 2/3(x-9)=1/3(2x-6) equation:

2/3(x-9)=1/3(2x-6)

We move all terms to the left:

2/3(x-9)-(1/3(2x-6))=0


Domain of the equation: 3(x-9)!=0

x∈R



Domain of the equation: 3(2x-6))!=0

x∈R


We calculate fractions


(6x2/(3(x-9)*3(2x-6)))+(-3xx/(3(x-9)*3(2x-6)))=0


We calculate terms in parentheses: +(6x2/(3(x-9)*3(2x-6))), so:

6x2/(3(x-9)*3(2x-6))

We multiply all the terms by the denominator


6x2

We add all the numbers together, and all the variables

6x^2

Back to the equation:

+(6x^2)



We calculate terms in parentheses: +(-3xx/(3(x-9)*3(2x-6))), so:

-3xx/(3(x-9)*3(2x-6))

We multiply all the terms by the denominator


-3xx

Back to the equation:

+(-3xx)


We get rid of parentheses

6x^2-3xx=0