2/3(y+1)=y-1

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Solution for 2/3(y+1)=y-1 equation: 



2/3(y+1)=y-1

We move all terms to the left:

2/3(y+1)-(y-1)=0



Domain of the equation: 3(y+1)!=0

y∈R



We get rid of parentheses

2/3(y+1)-y+1=0

We multiply all the terms by the denominator


-y*3(y+1)+1*3(y+1)+2=0

Wy multiply elements

-3y^2(y+3y(y+2=0

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