2/3(y+18)=1/3y+10

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Solution for 2/3(y+18)=1/3y+10 equation: 



2/3(y+18)=1/3y+10

We move all terms to the left:

2/3(y+18)-(1/3y+10)=0



Domain of the equation: 3(y+18)!=0

y∈R





Domain of the equation: 3y+10)!=0

y∈R



We get rid of parentheses

2/3(y+18)-1/3y-10=0

We calculate fractions


6y/(9y^2+162y)+(-3yy/(9y^2+162y)-10=0

We calculate fractions

We do not support eypression: y^3

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