2/3(y+4)=y-4

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Solution for 2/3(y+4)=y-4 equation: 



2/3(y+4)=y-4

We move all terms to the left:

2/3(y+4)-(y-4)=0



Domain of the equation: 3(y+4)!=0

y∈R



We get rid of parentheses

2/3(y+4)-y+4=0

We multiply all the terms by the denominator


-y*3(y+4)+4*3(y+4)+2=0

Wy multiply elements

-3y^2(y+12y(y+2=0

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