2/3(y-10)=-4y-20

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Solution for 2/3(y-10)=-4y-20 equation: 



2/3(y-10)=-4y-20

We move all terms to the left:

2/3(y-10)-(-4y-20)=0



Domain of the equation: 3(y-10)!=0

y∈R



We get rid of parentheses

2/3(y-10)+4y+20=0

We multiply all the terms by the denominator


4y*3(y-10)+20*3(y-10)+2=0

Wy multiply elements

12y^2(y+60y(y+2=0

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