2/3(y-3)=1/3(y+6)

Solution for 2/3(y-3)=1/3(y+6) equation:

2/3(y-3)=1/3(y+6)

We move all terms to the left:

2/3(y-3)-(1/3(y+6))=0


Domain of the equation: 3(y-3)!=0

y∈R



Domain of the equation: 3(y+6))!=0

y∈R


We calculate fractions


(6yy/(3(y-3)*3(y+6)))+(-3yy/(3(y-3)*3(y+6)))=0


We calculate terms in parentheses: +(6yy/(3(y-3)*3(y+6))), so:

6yy/(3(y-3)*3(y+6))

We multiply all the terms by the denominator


6yy

Back to the equation:

+(6yy)



We calculate terms in parentheses: +(-3yy/(3(y-3)*3(y+6))), so:

-3yy/(3(y-3)*3(y+6))

We multiply all the terms by the denominator


-3yy

Back to the equation:

+(-3yy)


We get rid of parentheses

6yy-3yy=0