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2/3(y-9)=3/4(y=8)
We move all terms to the left:
2/3(y-9)-(3/4(y)=0
Domain of the equation: 3(y-9)!=0
y∈R
Domain of the equation: 4y!=0We calculate fractions
y!=0/4
y!=0
y∈R
8y/(12y^2-108y)+(-9yy/(12y^2-108y)=0
We calculate terms in parentheses: +(-9yy/(12y^2-108y), so:We get rid of parentheses
-9yy/(12y^2-108y
We multiply all the terms by the denominator
-9yy
Back to the equation:
+(-9yy)
8y/(12y^2-108y)-9yy=0
We multiply all the terms by the denominator
8y-9yy*(12y^2-108y)=0
We multiply parentheses
-108y^3+972y^2+8y=0
We do not support eypression: y^3
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