2/3(z+1)=y

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Solution for 2/3(z+1)=y equation: 


x in (-oo:+oo)

(2/3)*(z+1) = y // - y

(2/3)*(z+1)-y = 0

2/3*(z+1)-y = 0

2/3*(z+1)-y = 0

2/3*z-y+2/3 = 0

2/3*z-y+2/3 = 0

x belongs to the empty set

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