2/3(z+5)+z=30

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Solution for 2/3(z+5)+z=30 equation: 



2/3(z+5)+z=30

We move all terms to the left:

2/3(z+5)+z-(30)=0



Domain of the equation: 3(z+5)!=0

z∈R



We add all the numbers together, and all the variables

z+2/3(z+5)-30=0

We multiply all the terms by the denominator


z*3(z+5)-30*3(z+5)+2=0

Wy multiply elements

3z^2(z-90z(z+2=0

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