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2/3(4x+16)=16*12x
We move all terms to the left:
2/3(4x+16)-(16*12x)=0
Domain of the equation: 3(4x+16)!=0We add all the numbers together, and all the variables
x∈R
2/3(4x+16)-(+16*12x)=0
We get rid of parentheses
2/3(4x+16)-16*12x=0
We multiply all the terms by the denominator
-(16*12x)*3(4x+16)+2=0
We add all the numbers together, and all the variables
-(+16*12x)*3(4x+16)+2=0
We move all terms containing x to the left, all other terms to the right
-(+16*12x)*3(4x+16)=-2
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