2/3*m+5=17

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Solution for 2/3*m+5=17 equation: 



2/3m+5=17

We move all terms to the left:

2/3m+5-(17)=0



Domain of the equation: 3m!=0

m!=0/3

m!=0

m∈R



We add all the numbers together, and all the variables

2/3m-12=0

We multiply all the terms by the denominator


-12*3m+2=0

Wy multiply elements

-36m+2=0

We move all terms containing m to the left, all other terms to the right

-36m=-2

m=-2/-36

m=1/18

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