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2/3*x-4=-2
We move all terms to the left:
2/3*x-4-(-2)=0
Domain of the equation: 3*x!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
2/3*x-2=0
We multiply all the terms by the denominator
-2*3*x+2=0
Wy multiply elements
-6x*x+2=0
Wy multiply elements
-6x^2+2=0
a = -6; b = 0; c = +2;
Δ = b2-4ac
Δ = 02-4·(-6)·2
Δ = 48
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{48}=\sqrt{16*3}=\sqrt{16}*\sqrt{3}=4\sqrt{3}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{3}}{2*-6}=\frac{0-4\sqrt{3}}{-12} =-\frac{4\sqrt{3}}{-12} =-\frac{\sqrt{3}}{-3} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{3}}{2*-6}=\frac{0+4\sqrt{3}}{-12} =\frac{4\sqrt{3}}{-12} =\frac{\sqrt{3}}{-3} $
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