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2/3+3x-3x=4x-5/6-3x
We move all terms to the left:
2/3+3x-3x-(4x-5/6-3x)=0
Domain of the equation: 6-3x)!=0We add all the numbers together, and all the variables
We move all terms containing x to the left, all other terms to the right
-3x)!=-6
x!=-6/1
x!=-6
x∈R
3x-3x-(+x-5/6)+2/3=0
We add all the numbers together, and all the variables
-(+x-5/6)+2/3=0
We get rid of parentheses
-x+5/6+2/3=0
We calculate fractions
There is no solution for this equation
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